9x^2-41x-204=0

Solution for 9x^2-41x-204=0 equation:

9x^2-41x-204=0

a = 9; b = -41; c = -204;
Δ = b2-4ac
Δ = -412-4·9·(-204)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-95}{2*9}=\frac{-54}{18}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+95}{2*9}=\frac{136}{18}
=7+5/9
$